Let’s Get Functional – SAT Math Question of the Day

Tuesday, July 21, 2015The Ready4 Team

2 thoughts on “Let’s Get Functional – SAT Math Question of the Day”

as someone used to long procedures,i found this app very interesting especially the shortcuts used to solve the problems. I only had one problem with the question on July 21,2015. I still think my answer (A) is correct because in the question, t is said to be more than zero. I need your feedback please. thank u

Hey Mohammed,

Yes, you’re right: t is said to be greater than zero, so using t = 0 as a starting point doesn’t appear correct. However, the correct answer is still D. Take for instance if t = .5 .

.5 is greater than zero, and when t = .5, r is -.4375.
Then when t is 1, r is -1.
And when t is 2, r is 8.
And when t is 3, r is 63 and so forth.

The change from -.4375 to -1 is a decrease because -1 is further away from zero than -.4375 .

So as t increases from above zero (for example, imagine the smallest possible decibel above zero), r initially decreases and then increases.

as someone used to long procedures,i found this app very interesting especially the shortcuts used to solve the problems. I only had one problem with the question on July 21,2015. I still think my answer (A) is correct because in the question, t is said to be more than zero. I need your feedback please. thank u

Hey Mohammed,

Yes, you’re right: t is said to be greater than zero, so using t = 0 as a starting point doesn’t appear correct. However, the correct answer is still D. Take for instance if t = .5 .

.5 is greater than zero, and when t = .5, r is -.4375.

Then when t is 1, r is -1.

And when t is 2, r is 8.

And when t is 3, r is 63 and so forth.

The change from -.4375 to -1 is a decrease because -1 is further away from zero than -.4375 .

So as t increases from above zero (for example, imagine the smallest possible decibel above zero), r initially decreases and then increases.

Hope this helps!